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Re: total inductance of bucking coils
| General Patron | 28 Feb 2009 07:17 |
Brett Holden said the following on 2009-02-05 17:05:
> What are you, the Usenet police? No he is not, that would be me.
> Thanks for NOTHING. YW.
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| Brett Holden | 05 Feb 2009 16:05 |
What are you, the Usenet police? I thought maybe you'd have an answer. Thanks for NOTHING.
> What's your application, what do you want to know that for. > [quoted text clipped - 35 lines] >> >> Thanks for your help! |
| Shaun | 31 Jan 2009 03:51 |
What's your application, what do you want to know that for.
You not one of those free energy nuts are you?
>I need to be able to calculate the total inductance of two coupled coils >when one coil is wound in reverse. I have a Boylestad's Introductory [quoted text clipped - 31 lines] > > Thanks for your help! |
| Brett Holden | 31 Jan 2009 01:10 |
I need to be able to calculate the total inductance of two coupled coils when one coil is wound in reverse. I have a Boylestad's Introductory Circuit Analysis (old - 6th edition) that has a section covering this but I have run into a problem because there seems to be some circular reasoning in defining the equation (#1). (I have used brackets in place of subscripts.)
Inductance of two coupled, bucking coils: 1) L[T-] = L[1] + L[2] - 2M[1,2]
2) M = .25( L[t+] - L[t-] )
3) L[t+] = L1 + L2 + 2M[1,2]
4) L[t-] = L1 + L2 - 2M[1,2]
I can't use subscripts here, so formula 1 is supposed to read: "total inductance of two reverse wound (coupled) coils equals inductance L1 plus inductance L2, minus (two times their mutual inductance)".
OK, if we can define the mutual inductance "M", then all is well.
To define M, formula 2 seems simple enough but introduces two more variables, L[t+] and L[t-].
In formulas 3 and 4, variables L[t+] and L[t-] are defined, but M is used as a variable, so I am grasping thin air. Can somebody please help me out?
Also, formula 1 seems to ignore the influence of coeffecient of coupling between the coils but maybe that is accounted for in equations 3 and 4? (headache)
Thanks for your help!
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