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odd(?) transistor switch behaviour

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tempus fugit - 26 Feb 2007 14:49 GMT
Hey all;

Still plugging away at getting my pedalboard pop free. I use a transistor to
switch amp functions, as shown below:

                               +15v

                                |
 control voltage       ___    |/
           o--------o-|___|- -|
                        3k    |>
                                |
                                o
                                |
                                |
                                |
                                o
                               GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)

The 15v is from the amp, and switching it to ground turns the amp function
on or off (e.g. channel switching, volume boost). It switches dead quiet in
one direction, but there is a pop when I switch back. I put the circuit on
the scope, and found that it switches cleanly to ground, but when I switch
back, there is a little spike in the waveform just before the beam goes to a
higher position on the screen. I assume that this is my audible pop.

Any ideas as to why it's there and how to get rid of it?

Thanks
James Beck - 26 Feb 2007 15:31 GMT
> Hey all;
>
[quoted text clipped - 27 lines]
>
> Thanks

My best guess is that the entire circuit jumps to +15V when you kill the
ground to it.  It is still connected to the amp's ground and when the
coupling caps charge to +15 the thing pops.  Try using a high side
switch and see if that helps (a PNP switching the +15V).

                         Jim
tempus fugit - 27 Feb 2007 16:24 GMT
> > Hey all;
> >
[quoted text clipped - 34 lines]
>
>                           Jim

I'm gonna check and see if I have any PNPs sitting around here and give that
a try. I wish I'd have thought of that before I built the circuit into my
pedalboard - I wouldn't have needed to use an inverter to get the control
voltage right.

Thanks
Eeyore - 26 Feb 2007 15:45 GMT
> Hey all;
>
[quoted text clipped - 25 lines]
>
> Any ideas as to why it's there and how to get rid of it?

Try a much higher value base resistor. Just a hunch.

Graham
tempus fugit - 27 Feb 2007 16:29 GMT
> > Hey all;
> >
[quoted text clipped - 29 lines]
>
> Graham

Hi Graham;

Thanks again for the insight. I'll try a higher resistor while it's hooked
up to the scope, but I can't actually use a higher resistor on the
pedalboard. The 15v comes from the amp through a 100k resistor, and the Ron
of the transistor is too high to actually fully switch functions if I use
more than 3k (actually it still doesn't quite fully switch with 3K, but I
cant go any lower because it's being driven by a 4049.).
Eeyore - 27 Feb 2007 20:51 GMT
> "Eeyore" <rabbitsfriendsandrelations@hotmail.com> wrote in message
> >
[quoted text clipped - 3 lines]
> up to the scope, but I can't actually use a higher resistor on the
> pedalboard. The 15v comes from the amp through a 100k resistor,

So that's 150 uA.

With a typical small signal NPN device you'll need no more than 3uA of base
current to switch that !

> and the Ron of the transistor is too high to actually fully switch functions
> if I use
> more than 3k

Eh ?

That makes no sense at all..

Graham
tempus fugit - 28 Feb 2007 02:14 GMT
> > "Eeyore" <rabbitsfriendsandrelations@hotmail.com> wrote in message
> > >
[quoted text clipped - 18 lines]
>
> Graham

OK I'm glad this came up because it's been puzzling me for a while. The amp
has an LED indicator for each channel, so whichever one is on has its LED
lit. If I ground the connector (i.e., 15v to ground) the channels switch and
1 LED is on. However, if I connect the 15v to ground using a 15ohm resistor,
one LED will light fully, and the other will still be partially (or fully)
on. The same goes when using a transistor as a switch. I originally used a
10k resistor for the base, but 1 LED remained partially on. Using a lower
value resistor (like 3k) turns the LED almost completely off. I figured from
this that driving the base with more current reduced the Ron to a low enough
value that it switched completely. It does seem odd, though, with a 100k
resistor in there that an extra few ohms would make that much of a
difference. You may remember from my previous posts on this topic that I was
going to try a low Ron N-channel MOSFET to get away from this problem. Also,
I've tried using an optoisolator to do the switching, but it also leaves one
LED partially or fully lit.

Can you shed some light on this (no pun intended).

Thanks

Oh, one other quick question - I'm using a 4049 inverter set up to be a
latching flipflop and it seems to have died on me. When the input of any of
the inverters is grounded, its output should be a logic high shouldn't it?
I've been testing the various inverters in the package to see if there is
only one damaged or if the  whole thing is shot, and none of them give a
logic high with the input grounded, although they do show 0VDC when a high
is applied to the input.
John Fields - 26 Feb 2007 18:30 GMT
>Hey all;
>
[quoted text clipped - 25 lines]
>
>Any ideas as to why it's there and how to get rid of it?

---

                               +15v
                                |
                                +----+
                                |    |
                                | [100nF]
 control voltage       ___    |/     |
           o--------o-|___|- -|     GND
                        3k    |>
                                |
                                o
                                |
                                |
                                |
                                o
                               GND

Signature

JF

tempus fugit - 27 Feb 2007 16:30 GMT
> >Hey all;
> >
[quoted text clipped - 43 lines]
>                                  o
>                                 GND

Thanks for the tip John. I'll scrounge up a 100nF cap and see if that fixes
things. Also, is the value critical? I'm assuming not, but I'm just
wondering how you decided on 100nF.

Thanks again
John Fields - 27 Feb 2007 17:57 GMT
>> ---
>>
[quoted text clipped - 17 lines]
>things. Also, is the value critical? I'm assuming not, but I'm just
>wondering how you decided on 100nF.

---
WAG, basically. ;) I figured the 15V was coming from a pullup, and I
thought it likely to be somewhere between 10k and 100k, so 100nF
would give a time constant of 1ms at 10k and 10ms at 100k.  What it
does is increase the time it takes for the transistor end of the
pullup to get back to 15V, so that should also "soften up" the
notch.  The value isn't critical except that it might be too small.
It occurs to me that the notch might also be in the switching signal
on the base, so you might want to look at that line and filter it if
you find the notch there.  Which transistor are you using?

Signature

JF

tempus fugit - 27 Feb 2007 18:45 GMT
> >> ---
> >>
[quoted text clipped - 28 lines]
> on the base, so you might want to look at that line and filter it if
> you find the notch there.  Which transistor are you using?

Thanks again John. The transistor is a generic 2222.
Eeyore - 27 Feb 2007 21:03 GMT
> I'm just wondering how you decided on 100nF.

He sucked his finger.

It's amazing how often 0.1 uF comes up as a result of that.

Graham
John Fields - 27 Feb 2007 21:29 GMT
>> I'm just wondering how you decided on 100nF.
>
>He sucked his finger.
>
>It's amazing how often 0.1 uF comes up as a result of that.

---
Awww... Poor baby's upset because she couldn't come up with it no
matter what she sucked. :-(

Signature

JF

 
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