>John Popelish a écrit :
>
[quoted text clipped - 53 lines]
>* I am from the opamp generation and I am trying to improve my
>transistor skills, that's why I am playing with this.
Hmm. Staying with the degenerative amplifier and in keeping with your
suggestion that as little as 2V is okay, you might try this:
>: +9
>: +9 |
[quoted text clipped - 25 lines]
>: | |
>: gnd gnd
I haven't wired it up, but I think it should be about right.
You could dump R5 (short it) and C3 (remove it.) Won't work quite as
well, but might be fine.
Quiescent current is set at 1mA.
If you need explanations, I can walk through your questions, I think.
Jon
> John Popelish a écrit :
>>I suggest you simplify your circuit to make it more of a switching
>>output than a linear amplifier. TTL sources generally are a lot
[quoted text clipped - 6 lines]
> That's what I did in the first place, except that I had picked 4k7 for
> R1, but the output stuck low all the time.
That tels me one of two things were happening. Either the stored
charge in the base did not have time to drain during the input low
periods, or the input was not really TTL level. TTL outputs typically
pull down to a small fraction of a volt above ground, if they are not
sinking significant current. A lower value base resistor allows the
stored charge to drain faster through the small voltage drop across
the resistor (.6 volts at the base and, say, .25 volts from the TTL
source). The base drive would be excessive during the logic high
state, except that TTL outputs do not pull up well, above about 2.5
volts, so it isn't so bad, unless you need the source to also drive
some other input at a larger voltage swing.
> I thought that maybe the
> transistor had problems of coming out ot saturation (is that why you
> suggest such a small R1? *) so I tried a simple amplifier to stay out
> of saturation. The shape of the output was not really a concern as long
> as it would swing from about 2V to 8V.
What, exactly is the signal source for the transistor? Have you an
oscilloscope to measure it and other nodes during operation?
> * I am from the opamp generation and I am trying to improve my
> transistor skills, that's why I am playing with this.
Understood. The problem may not be with the transistor, but with the
signal source.
Here is another approach for you to play with. Use the transistor as
a common base amplifier (voltage gain, but no current gain, and non
inverting). Tie the base to the center node of a resistive voltage
divider made up of two 10k or 4.7k resistors tied between +5 and
ground. Connect your signal source to the emitter and connect the
collector to a 4.7k or 10k pull up resistor to the 9 volt supply (or
whatever voltage is the positive rail for th CMOS chip).
When the TTL signal is positive, the base-emitter junction is reverse
biased, and the collector pull up resistor provides a full positive
output. When the TTL input pulls down to almost zero, the
base-emitter junction is forward biased (with the base current limited
by the divider total resistance) and the transistor saturates on,
pulling the output down to the TTL low voltage plus the transistor
saturation voltage. You lose some of the TTL pull down current
capability into the base divider, but you get more voltage swing than
the TTL signal delivers.
Jenalee K. - 29 Sep 2006 09:13 GMT
John Popelish a écrit :
> > John Popelish a écrit :
>
[quoted text clipped - 29 lines]
> What, exactly is the signal source for the transistor? Have you an
> oscilloscope to measure it and other nodes during operation?
Good question. I was driving it with an old crystal oscillator (Kony
KHC1100 1MHz) that I had found somewhere and I supposed it was TTL. But
I can't find any information on it, except that it is apparently
obsolete, and so it may be an HCMOS device.
And yes, I have access to a good oscilloscope.
I will try your suggestions as well as those from all those kind other
repliers. I will also try with different signal sources so that I do
know for sure what kind of driver I have.
Thanks,
Jenalee K.
>> > I wanted to amplify a TTL-level 1MHz square wave a bit so that it can
>> > be used as a clock for a CMOS counter running from 9V. According to
>> > LT-Spice the circuit below works fine, but the real world does not
>> > agree (at all). Actually I measured a cut-off frequency of 165kHz and
>> > at 1MHz not much is left. Why is the simulation so wrong? 1MHz isn't
>> > that high is it?
Try this, both because it will work, and because it's sort of
interesting...
>> > VCC
>> > +
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>> > |
>> > gnd
John