I know. The magnetic field needs time to collapse. I'm asking does
the mag field collapse faster with fewer
turns on N1'.
>> > Looking at the forward converter topology illustrated here:
>> > http://schmidt-walter.fbe.fh-darmstadt.de/smps_e/edw_hilfe_e.html
[quoted text clipped - 9 lines]
> the mag field collapse faster with fewer
> turns on N1'.
Yes. However, note that the transistor's drain voltage would then be
Vin+(N1*Vin/N1'). The series diode on the secondary would also see higher
voltage (Vin*N2/N1').
John
kell - 29 Nov 2005 05:20 GMT
> Yes. However, note that the transistor's drain voltage would then be
> Vin+(N1*Vin/N1').
Ouch.
kell - 29 Nov 2005 05:23 GMT
> Yes. However, note that the transistor's drain voltage would then be
> Vin+(N1*Vin/N1').
That means when N1=N1', drain voltage is 2Vin. I didn't know that.
John - KD5YI - 29 Nov 2005 14:55 GMT
>>Yes. However, note that the transistor's drain voltage would then be
>>Vin+(N1*Vin/N1').
>
> That means when N1=N1', drain voltage is 2Vin. I didn't know that.
You must have missed it. 5th paragraph below the schematic it says...
"Due to this the transistor drain-source voltage steps up to Vds > 2Vin when
the transistor is turned off."
Sorry.
John