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forward converter duty cycle question

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kell - 26 Nov 2005 05:13 GMT
Looking at the forward converter topology illustrated here:
http://schmidt-walter.fbe.fh-darmstadt.de/smps_e/edw_hilfe_e.html
They specify a maximum duty cycle of 50%.
Is this predicated on N1 and N1' having an equal number of turns?
It seems to me you get a longer duty cycle by reducing the number of
turns on N1'.
John - kd5yi - 27 Nov 2005 02:56 GMT
> Looking at the forward converter topology illustrated here:
> http://schmidt-walter.fbe.fh-darmstadt.de/smps_e/edw_hilfe_e.html
> They specify a maximum duty cycle of 50%.
> Is this predicated on N1 and N1' having an equal number of turns?
> It seems to me you get a longer duty cycle by reducing the number of
> turns on N1'.

I think it's to keep the transformer from saturating.

John
kell - 28 Nov 2005 01:45 GMT
> > Looking at the forward converter topology illustrated here:
> > http://schmidt-walter.fbe.fh-darmstadt.de/smps_e/edw_hilfe_e.html
[quoted text clipped - 6 lines]
>
> John
I know.  The magnetic field needs time to collapse.  I'm asking does
the mag field collapse faster with fewer
turns on N1'.
John - kd5yi - 28 Nov 2005 14:40 GMT
>> > Looking at the forward converter topology illustrated here:
>> > http://schmidt-walter.fbe.fh-darmstadt.de/smps_e/edw_hilfe_e.html
[quoted text clipped - 9 lines]
> the mag field collapse faster with fewer
> turns on N1'.

Yes. However, note that the transistor's drain voltage would then be
Vin+(N1*Vin/N1'). The series diode on the secondary would also see higher
voltage (Vin*N2/N1').

John
kell - 29 Nov 2005 05:20 GMT
> Yes. However, note that the transistor's drain voltage would then be
> Vin+(N1*Vin/N1').

Ouch.
kell - 29 Nov 2005 05:23 GMT
> Yes. However, note that the transistor's drain voltage would then be
> Vin+(N1*Vin/N1').

That means when N1=N1', drain voltage is 2Vin.  I didn't know that.
John - KD5YI - 29 Nov 2005 14:55 GMT
>>Yes. However, note that the transistor's drain voltage would then be
>>Vin+(N1*Vin/N1').
>
> That means when N1=N1', drain voltage is 2Vin.  I didn't know that.

You must have missed it. 5th paragraph below the schematic it says...

"Due to this the transistor drain-source voltage steps up to Vds > 2Vin when
the transistor is turned off."

Sorry.

John
 
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